- #23 [堯軍], 17-06-28 09:04呢類數比較有印象應該係 nCr 同 nPr, 日常用嚟計六合彩或賽馬複式注數
- #22 [F355], 17-06-28 02:13出黎做野十幾年,呢d數基本上已忘記晒,
如果我仲記得,今日可能已經係醫生或者律師.... - #21 [呀金], 17-06-28 01:39新高中仲要學生選 Extended Maths 才會有比較深既內容.
中二根本都未選科, 正常唔可能要計呢類題目! -
- #20 [2628939], 17-06-28 01:22中五會考嘅A. Maths(附加數)嘅Mathematical induction(數學歸納)可以證明之。
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CHING, sorry, 新高中冇A. Maths(附加數),好多學生怕唔識Mathematical induction... - #19 [2,4-DPN], 17-06-27 22:47#6如果 given formula 就易,要 prove 埋就睇怕要大學 level 呱?!吾洗U level架,用中五會考嘅A. Maths(附加數)嘅Mathematical induction(數學歸納)可以證明之。#12佢今日話用 Logarithm 可以做到。對,因為用二項式(binomial theory)要中四和程度嘅A.Maths先會學,佢中二,只可以用log做。
- #18 [bluejay], 17-06-27 07:49wrong post, sorry.
最後修改時間: 2017-06-27 07:54:06 - #17 [lanevo], 17-06-27 06:38正常課書之前會提過有這些公式,之後才會出這些題目。但莫非現在已經進化到要google search 返條公式來作答?
- #16 [bankguy], 17-06-27 00:30我投降。
- #15 [ocisgood], 17-06-27 00:27佢一定教過sum ((k^n)-(k-1)^n)=K^n
然後佢應該教過binomial theorem (k-1)^n=k^n-n(k^(n-1))......
只要用k^4-(k-1)^4, 已見到答案咁滯 - #14 [bankguy], 17-06-27 00:20嘩!師兄好勁。我睇到眼都花。
- #13 [ocisgood], 17-06-27 00:13佢應該敎過過解power series方法的.
summation from 1 to n (k^4-(k-1)^4)=n^4
k^4-(k-1)^4=4*n^3-6*n^2+4^n-1
sum of LHS=n^4
sum of RHS = 2(sum(2*n^3-3*n^2+2*n))-n
所以sum( )=(n^4+n)/2
summation K^n 用呢個方法solve
summation from 1 to n (k^4-(k-1)^4)=n^4
=(1^4-0^4)+(2^4-1^4)+(3^4-2^4)+......(n^4-(n-1)^4)=n^4
最後修改時間: 2017-06-27 00:18:47 - #12 [bankguy], 17-06-26 23:49如果仔仔有聽書, 佢可以在1分鐘內計到答案係(100^4+100)/2.
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願聞其詳。
佢今日話用 Logarithm 可以做到。 - #11 [ocisgood], 17-06-26 23:07如果仔仔有聽書, 佢可以在1分鐘內計到答案係(100^4+100)/2.
- #10 [danny-love], 17-06-26 20:52睇到我眼都花
- #9 [bankguy], 17-06-26 20:49我只知係 Math Competition.
- #8 [japhetj], 17-06-26 20:28Form2? 邊間學校? 推佢上報啦。
- #7 [bankguy], 17-06-26 20:12我叫姨甥有 solution 就 send 俾我,等我睇吓有幾痴線。Form 2 學生要做呢啲數?
- #6 [bankguy], 17-06-26 19:40
- #5 [bankguy], 17-06-25 20:13原來係 math competition 問題,咁鬼難!
- #4 [bankguy], 17-06-25 19:50唔該哂師兄,唔明 Form 2 學生要識呢啲?
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